(4x-5)^0=(x+90)

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Solution for (4x-5)^0=(x+90) equation: 



(4x-5)^0=(x+90)

We move all terms to the left:

(4x-5)^0-((x+90))=0



We calculate terms in parentheses: -((x+90)), so:

(x+90)

We get rid of parentheses

x+90

Back to the equation:

-(x+90)



We get rid of parentheses

(4x-5)^0-x-90=0

We add all the numbers together, and all the variables

-1x+(4x-5)^0-90=0

We move all terms containing x to the left, all other terms to the right

-1x+(4x-5)^0=90

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